Integrand size = 14, antiderivative size = 161 \[ \int x^4 \left (a+b \arctan \left (c x^2\right )\right ) \, dx=-\frac {2 b x^3}{15 c}+\frac {1}{5} x^5 \left (a+b \arctan \left (c x^2\right )\right )-\frac {b \arctan \left (1-\sqrt {2} \sqrt {c} x\right )}{5 \sqrt {2} c^{5/2}}+\frac {b \arctan \left (1+\sqrt {2} \sqrt {c} x\right )}{5 \sqrt {2} c^{5/2}}+\frac {b \log \left (1-\sqrt {2} \sqrt {c} x+c x^2\right )}{10 \sqrt {2} c^{5/2}}-\frac {b \log \left (1+\sqrt {2} \sqrt {c} x+c x^2\right )}{10 \sqrt {2} c^{5/2}} \]
[Out]
Time = 0.08 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.571, Rules used = {4946, 327, 303, 1176, 631, 210, 1179, 642} \[ \int x^4 \left (a+b \arctan \left (c x^2\right )\right ) \, dx=\frac {1}{5} x^5 \left (a+b \arctan \left (c x^2\right )\right )-\frac {b \arctan \left (1-\sqrt {2} \sqrt {c} x\right )}{5 \sqrt {2} c^{5/2}}+\frac {b \arctan \left (\sqrt {2} \sqrt {c} x+1\right )}{5 \sqrt {2} c^{5/2}}+\frac {b \log \left (c x^2-\sqrt {2} \sqrt {c} x+1\right )}{10 \sqrt {2} c^{5/2}}-\frac {b \log \left (c x^2+\sqrt {2} \sqrt {c} x+1\right )}{10 \sqrt {2} c^{5/2}}-\frac {2 b x^3}{15 c} \]
[In]
[Out]
Rule 210
Rule 303
Rule 327
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 4946
Rubi steps \begin{align*} \text {integral}& = \frac {1}{5} x^5 \left (a+b \arctan \left (c x^2\right )\right )-\frac {1}{5} (2 b c) \int \frac {x^6}{1+c^2 x^4} \, dx \\ & = -\frac {2 b x^3}{15 c}+\frac {1}{5} x^5 \left (a+b \arctan \left (c x^2\right )\right )+\frac {(2 b) \int \frac {x^2}{1+c^2 x^4} \, dx}{5 c} \\ & = -\frac {2 b x^3}{15 c}+\frac {1}{5} x^5 \left (a+b \arctan \left (c x^2\right )\right )-\frac {b \int \frac {1-c x^2}{1+c^2 x^4} \, dx}{5 c^2}+\frac {b \int \frac {1+c x^2}{1+c^2 x^4} \, dx}{5 c^2} \\ & = -\frac {2 b x^3}{15 c}+\frac {1}{5} x^5 \left (a+b \arctan \left (c x^2\right )\right )+\frac {b \int \frac {1}{\frac {1}{c}-\frac {\sqrt {2} x}{\sqrt {c}}+x^2} \, dx}{10 c^3}+\frac {b \int \frac {1}{\frac {1}{c}+\frac {\sqrt {2} x}{\sqrt {c}}+x^2} \, dx}{10 c^3}+\frac {b \int \frac {\frac {\sqrt {2}}{\sqrt {c}}+2 x}{-\frac {1}{c}-\frac {\sqrt {2} x}{\sqrt {c}}-x^2} \, dx}{10 \sqrt {2} c^{5/2}}+\frac {b \int \frac {\frac {\sqrt {2}}{\sqrt {c}}-2 x}{-\frac {1}{c}+\frac {\sqrt {2} x}{\sqrt {c}}-x^2} \, dx}{10 \sqrt {2} c^{5/2}} \\ & = -\frac {2 b x^3}{15 c}+\frac {1}{5} x^5 \left (a+b \arctan \left (c x^2\right )\right )+\frac {b \log \left (1-\sqrt {2} \sqrt {c} x+c x^2\right )}{10 \sqrt {2} c^{5/2}}-\frac {b \log \left (1+\sqrt {2} \sqrt {c} x+c x^2\right )}{10 \sqrt {2} c^{5/2}}+\frac {b \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} \sqrt {c} x\right )}{5 \sqrt {2} c^{5/2}}-\frac {b \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} \sqrt {c} x\right )}{5 \sqrt {2} c^{5/2}} \\ & = -\frac {2 b x^3}{15 c}+\frac {1}{5} x^5 \left (a+b \arctan \left (c x^2\right )\right )-\frac {b \arctan \left (1-\sqrt {2} \sqrt {c} x\right )}{5 \sqrt {2} c^{5/2}}+\frac {b \arctan \left (1+\sqrt {2} \sqrt {c} x\right )}{5 \sqrt {2} c^{5/2}}+\frac {b \log \left (1-\sqrt {2} \sqrt {c} x+c x^2\right )}{10 \sqrt {2} c^{5/2}}-\frac {b \log \left (1+\sqrt {2} \sqrt {c} x+c x^2\right )}{10 \sqrt {2} c^{5/2}} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.11 \[ \int x^4 \left (a+b \arctan \left (c x^2\right )\right ) \, dx=-\frac {2 b x^3}{15 c}+\frac {a x^5}{5}+\frac {1}{5} b x^5 \arctan \left (c x^2\right )+\frac {b \arctan \left (\frac {-\sqrt {2}+2 \sqrt {c} x}{\sqrt {2}}\right )}{5 \sqrt {2} c^{5/2}}+\frac {b \arctan \left (\frac {\sqrt {2}+2 \sqrt {c} x}{\sqrt {2}}\right )}{5 \sqrt {2} c^{5/2}}+\frac {b \log \left (1-\sqrt {2} \sqrt {c} x+c x^2\right )}{10 \sqrt {2} c^{5/2}}-\frac {b \log \left (1+\sqrt {2} \sqrt {c} x+c x^2\right )}{10 \sqrt {2} c^{5/2}} \]
[In]
[Out]
Time = 0.87 (sec) , antiderivative size = 121, normalized size of antiderivative = 0.75
method | result | size |
default | \(\frac {a \,x^{5}}{5}+b \left (\frac {x^{5} \arctan \left (c \,x^{2}\right )}{5}-\frac {2 c \left (\frac {x^{3}}{3 c^{2}}-\frac {\sqrt {2}\, \left (\ln \left (\frac {x^{2}-\left (\frac {1}{c^{2}}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {1}{c^{2}}}}{x^{2}+\left (\frac {1}{c^{2}}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {1}{c^{2}}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {1}{c^{2}}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {1}{c^{2}}\right )^{\frac {1}{4}}}-1\right )\right )}{8 c^{4} \left (\frac {1}{c^{2}}\right )^{\frac {1}{4}}}\right )}{5}\right )\) | \(121\) |
parts | \(\frac {a \,x^{5}}{5}+b \left (\frac {x^{5} \arctan \left (c \,x^{2}\right )}{5}-\frac {2 c \left (\frac {x^{3}}{3 c^{2}}-\frac {\sqrt {2}\, \left (\ln \left (\frac {x^{2}-\left (\frac {1}{c^{2}}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {1}{c^{2}}}}{x^{2}+\left (\frac {1}{c^{2}}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {1}{c^{2}}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {1}{c^{2}}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {1}{c^{2}}\right )^{\frac {1}{4}}}-1\right )\right )}{8 c^{4} \left (\frac {1}{c^{2}}\right )^{\frac {1}{4}}}\right )}{5}\right )\) | \(121\) |
[In]
[Out]
Result contains complex when optimal does not.
Time = 0.26 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.06 \[ \int x^4 \left (a+b \arctan \left (c x^2\right )\right ) \, dx=\frac {6 \, b c x^{5} \arctan \left (c x^{2}\right ) + 6 \, a c x^{5} - 4 \, b x^{3} + 3 \, c \left (-\frac {b^{4}}{c^{10}}\right )^{\frac {1}{4}} \log \left (c^{7} \left (-\frac {b^{4}}{c^{10}}\right )^{\frac {3}{4}} + b^{3} x\right ) - 3 i \, c \left (-\frac {b^{4}}{c^{10}}\right )^{\frac {1}{4}} \log \left (i \, c^{7} \left (-\frac {b^{4}}{c^{10}}\right )^{\frac {3}{4}} + b^{3} x\right ) + 3 i \, c \left (-\frac {b^{4}}{c^{10}}\right )^{\frac {1}{4}} \log \left (-i \, c^{7} \left (-\frac {b^{4}}{c^{10}}\right )^{\frac {3}{4}} + b^{3} x\right ) - 3 \, c \left (-\frac {b^{4}}{c^{10}}\right )^{\frac {1}{4}} \log \left (-c^{7} \left (-\frac {b^{4}}{c^{10}}\right )^{\frac {3}{4}} + b^{3} x\right )}{30 \, c} \]
[In]
[Out]
Time = 15.27 (sec) , antiderivative size = 153, normalized size of antiderivative = 0.95 \[ \int x^4 \left (a+b \arctan \left (c x^2\right )\right ) \, dx=\begin {cases} \frac {a x^{5}}{5} + \frac {b x^{5} \operatorname {atan}{\left (c x^{2} \right )}}{5} - \frac {2 b x^{3}}{15 c} + \frac {b \log {\left (x - \sqrt [4]{- \frac {1}{c^{2}}} \right )}}{5 c^{3} \sqrt [4]{- \frac {1}{c^{2}}}} - \frac {b \log {\left (x^{2} + \sqrt {- \frac {1}{c^{2}}} \right )}}{10 c^{3} \sqrt [4]{- \frac {1}{c^{2}}}} + \frac {b \operatorname {atan}{\left (\frac {x}{\sqrt [4]{- \frac {1}{c^{2}}}} \right )}}{5 c^{3} \sqrt [4]{- \frac {1}{c^{2}}}} - \frac {b \operatorname {atan}{\left (c x^{2} \right )}}{5 c^{6} \left (- \frac {1}{c^{2}}\right )^{\frac {7}{4}}} & \text {for}\: c \neq 0 \\\frac {a x^{5}}{5} & \text {otherwise} \end {cases} \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 147, normalized size of antiderivative = 0.91 \[ \int x^4 \left (a+b \arctan \left (c x^2\right )\right ) \, dx=\frac {1}{5} \, a x^{5} + \frac {1}{60} \, {\left (12 \, x^{5} \arctan \left (c x^{2}\right ) - c {\left (\frac {8 \, x^{3}}{c^{2}} - \frac {3 \, {\left (\frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (2 \, c x + \sqrt {2} \sqrt {c}\right )}}{2 \, \sqrt {c}}\right )}{c^{\frac {3}{2}}} + \frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (2 \, c x - \sqrt {2} \sqrt {c}\right )}}{2 \, \sqrt {c}}\right )}{c^{\frac {3}{2}}} - \frac {\sqrt {2} \log \left (c x^{2} + \sqrt {2} \sqrt {c} x + 1\right )}{c^{\frac {3}{2}}} + \frac {\sqrt {2} \log \left (c x^{2} - \sqrt {2} \sqrt {c} x + 1\right )}{c^{\frac {3}{2}}}\right )}}{c^{2}}\right )}\right )} b \]
[In]
[Out]
none
Time = 0.33 (sec) , antiderivative size = 169, normalized size of antiderivative = 1.05 \[ \int x^4 \left (a+b \arctan \left (c x^2\right )\right ) \, dx=\frac {1}{20} \, b c^{9} {\left (\frac {2 \, \sqrt {2} \sqrt {{\left | c \right |}} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (2 \, x + \frac {\sqrt {2}}{\sqrt {{\left | c \right |}}}\right )} \sqrt {{\left | c \right |}}\right )}{c^{12}} + \frac {2 \, \sqrt {2} \sqrt {{\left | c \right |}} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (2 \, x - \frac {\sqrt {2}}{\sqrt {{\left | c \right |}}}\right )} \sqrt {{\left | c \right |}}\right )}{c^{12}} - \frac {\sqrt {2} \log \left (x^{2} + \frac {\sqrt {2} x}{\sqrt {{\left | c \right |}}} + \frac {1}{{\left | c \right |}}\right )}{c^{10} {\left | c \right |}^{\frac {3}{2}}} + \frac {\sqrt {2} \sqrt {{\left | c \right |}} \log \left (x^{2} - \frac {\sqrt {2} x}{\sqrt {{\left | c \right |}}} + \frac {1}{{\left | c \right |}}\right )}{c^{12}}\right )} + \frac {3 \, b c x^{5} \arctan \left (c x^{2}\right ) + 3 \, a c x^{5} - 2 \, b x^{3}}{15 \, c} \]
[In]
[Out]
Time = 0.40 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.40 \[ \int x^4 \left (a+b \arctan \left (c x^2\right )\right ) \, dx=\frac {a\,x^5}{5}-\frac {2\,b\,x^3}{15\,c}+\frac {b\,x^5\,\mathrm {atan}\left (c\,x^2\right )}{5}+\frac {{\left (-1\right )}^{1/4}\,b\,\mathrm {atan}\left ({\left (-1\right )}^{1/4}\,\sqrt {c}\,x\right )}{5\,c^{5/2}}+\frac {{\left (-1\right )}^{1/4}\,b\,\mathrm {atan}\left ({\left (-1\right )}^{1/4}\,\sqrt {c}\,x\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{5\,c^{5/2}} \]
[In]
[Out]